# 「POJ-2720」Last Digits-欧拉函数

Exponentiation of one integer by another often produces very large results. In this problem, we will compute a function based on repeated exponentiation, but output only the last n digits of the result. Doing this efficiently requires careful thought about how to avoid computing the full answer.

Given integers b, n, and i, we define the function f(x) recursively by f(x) = b f(x-1) if x > 0, and f(0)=1. Your job is to efficiently compute the last n decimal digits of f(i).

POJ-2720

# Math